Q 12-01-078JEE MainJEE Main 2023 (13 Apr, Shift 2)Easy
A $10\ \mu\text{C}$ charge is divided into two parts and placed at $1\ \text{cm}$ distance so that the repulsive force between them is maximum. The charges of the two parts are
Answer: (C) $5\ \mu\text{C},\ 5\ \mu\text{C}$
$F\propto q(Q-q)$ is maximum when $q=\dfrac Q2$: $5\ \mu\text{C}$ each.
Solution by Sreeraj P, M.Sc Physics