Q 12-01-059JEE MainJEE Main 2024 (8 Apr, Shift 1)Easy
An electric field $\vec E = \dfrac{2\hat i + 6\hat j + 8\hat k}{\sqrt6}$ passes through the surface of $4\ \text{m}^2$ area having unit vector $\hat n = \left(\dfrac{2\hat i + \hat j + \hat k}{\sqrt6}\right)$. The electric flux for that surface is ______ V m.
Numerical value type. Enter your answer.
Answer: 12
$$\Phi = \vec E\cdot\hat n\,A = \frac{(2)(2) + (6)(1) + (8)(1)}{6}\times4 = \frac{18}{6}\times4 = 12\ \text{V m}$$
Solution by Sreeraj P, M.Sc Physics