Q 12-01-043JEE MainJEE Main 2024 (1 Feb, Shift 2)Easy
$C_1$ and $C_2$ are two hollow concentric cubes enclosing charges $2Q$ and $3Q$ respectively as shown in the figure. The ratio of electric flux passing through $C_1$ and $C_2$ is
Answer: (A) $2:5$
By Gauss's law flux depends only on the enclosed charge.
$C_1$ encloses $2Q$: $\phi_1 = \dfrac{2Q}{\varepsilon_0}$.
$C_2$ encloses $2Q + 3Q = 5Q$: $\phi_2 = \dfrac{5Q}{\varepsilon_0}$.
$\phi_1 : \phi_2 = 2:5$.
Solution by Sreeraj P, M.Sc Physics