Q 12-01-013NEETJEE MainEasy
An electron is placed in a uniform electric field of $2 \times 10^4$ N/C. Its acceleration is ($e = 1.6 \times 10^{-19}$ C, $m_e = 9.1 \times 10^{-31}$ kg)
Answer: (A) $3.5 \times 10^{15}\ \text{m/s}^2$
$a = \dfrac{eE}{m} = \dfrac{1.6 \times 10^{-19} \times 2 \times 10^4}{9.1 \times 10^{-31}} \approx 3.5 \times 10^{15}\ \text{m/s}^2$, opposite to the field.
Solution by Sreeraj P, M.Sc Physics