Q 12-01-013NEETJEE MainEasy
An electron is placed in a uniform electric field of $2 \times 10^4$ N/C. Its acceleration is ($e = 1.6 \times 10^{-19}$ C, $m_e = 9.1 \times 10^{-31}$ kg)
Answer: (A) $3.5 \times 10^{15}\ \text{m/s}^2$
Concept. $a = \dfrac{eE}{m}$, directed opposite to the field for an electron.
Step 1. Substitute.
$$a = \frac{1.6 \times 10^{-19} \times 2 \times 10^4}{9.1 \times 10^{-31}} \approx 3.5 \times 10^{15}\ \text{m/s}^2$$
Answer. $3.5 \times 10^{15}$ m/s$^2$ (Option A).
Solution by Sreeraj P, M.Sc Physics