Q 12-11-179NEETNEET 2022Top questionEasy
The graph which shows the variation of the de Broglie wavelength ($\lambda$) of a particle and its associated momentum ($p$) is
Answer: (A) see figure
$\lambda = \dfrac{h}{p}$, so $\lambda p = h$ = constant.
The graph of $\lambda$ against $p$ is a rectangular hyperbola: $\lambda$ is very large for small $p$ and falls towards zero as $p$ grows. This is graph (1).
Solution by Sreeraj P, M.Sc Physics