Q 12-11-172JEE MainJEE Main 2018 (15 Apr, Shift 2)Easy
If the de Broglie wavelengths associated with a proton and an $\alpha$-particle are equal, then the ratio of velocities of the proton and the $\alpha$-particle will be:
Answer: (C) $4 : 1$
$\lambda = \dfrac{h}{mv}$. Equal wavelengths mean equal momenta, so
$$\frac{v_p}{v_\alpha} = \frac{m_\alpha}{m_p} = \frac{4}{1}$$
Solution by Sreeraj P, M.Sc Physics