Q 12-11-154JEE MainJEE Main 2020 (4 Sep, Shift 2)Easy
In a photoelectric effect experiment, the graph of stopping potential $V_s$ versus reciprocal of wavelength obtained is a straight line as shown in the figure. As the intensity of incident radiation is increased:
Answer: (D) Graph does not change
$eV_s = \dfrac{hc}{\lambda} - \phi$. Neither the slope $\dfrac{hc}{e}$ nor the intercept (set by $\phi$) depends on the intensity, which changes only the photocurrent. The graph does not change.
Solution by Sreeraj P, M.Sc Physics