Q 12-11-136JEE MainJEE Main 2021 (27 Aug, Shift 1)Easy
In a photoelectric experiment, increasing the intensity of incident light:
Answer: (C) increases the number of photons incident and the K.E. of the ejected electrons remains unchanged.
At a fixed frequency, higher intensity means more photons per second (so more photoelectrons), but each photon has the same energy $hf$. The maximum kinetic energy $hf - \phi$ is therefore unchanged.
Solution by Sreeraj P, M.Sc Physics