Q 12-11-100JEE MainJEE Main 2023 (1 Feb, Shift 1)Easy
A proton moving with one tenth of velocity of light has a certain de Broglie wavelength of $\lambda$. An alpha particle having certain kinetic energy has the same de Broglie wavelength $\lambda$. The ratio of kinetic energy of proton and that of alpha particle is
Answer: (B) $4:1$
Equal wavelengths mean equal momenta, and $K=\dfrac{p^2}{2m}$, so $\dfrac{K_p}{K_\alpha}=\dfrac{m_\alpha}{m_p}=4$.
Solution by Sreeraj P, M.Sc Physics