Q 12-11-089JEE MainJEE Main 2023 (15 Apr, Shift 1)Easy
The de Broglie wavelength of an electron having kinetic energy $E$ is $\lambda$. If the kinetic energy of electron becomes $\dfrac E4$, then its de-Broglie wavelength will be
Answer: (D) $2\lambda$
$\lambda=\dfrac{h}{\sqrt{2mE}}\propto\dfrac1{\sqrt E}$; $E\to\dfrac E4$ gives $2\lambda$.
Solution by Sreeraj P, M.Sc Physics