Q 12-11-071JEE MainJEE Main 2024 (8 Apr, Shift 2)Easy
A proton and an electron have the same de Broglie wavelength. If $K_p$ and $K_e$ be the kinetic energies of proton and electron respectively, then choose the correct relation:
Answer: (B) $K_p < K_e$
Equal wavelengths mean equal momenta. $K = \dfrac{p^2}{2m}$, and $m_p > m_e$, so $K_p < K_e$.
Solution by Sreeraj P, M.Sc Physics