A photon and an electron (mass m) have the same energy E. The ratio (λ_photon/λ_electron) of their de Broglie wavelengths is: (c is the speed of light)

(C) c√((2m)/(E)). Photon: λ_photon = (hc)/(E). Electron: λ_electron = h√(2mE). λ_photonλ_electron = hc/Eh/√(2mE) = c√(2mE)E = c√((2m)/(E))

Dual Nature of Radiation and Matter question for NEET (NEET 2025), with solution

Q 12-11-005NEETNEET 2025Top questionMedium

A photon and an electron (mass $m$) have the same energy $E$. The ratio ($\lambda_{\text{photon}}/\lambda_{\text{electron}}$) of their de Broglie wavelengths is: ($c$ is the speed of light)

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Dual Nature of Radiation and Matter question for NEET (NEET 2025), with solution

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