Q 12-03-296NEETNEET 2022Top questionEasy
Two resistors of resistance, $100\ \Omega$ and $200\ \Omega$ are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in $100\ \Omega$ to that in $200\ \Omega$ in a given time is
Answer: (C) $2 : 1$
In parallel both resistors have the same voltage $V$, so the heat produced in time $t$ is $H = \dfrac{V^2t}{R}$.
$$\frac{H_{100}}{H_{200}} = \frac{200}{100} = 2 : 1$$
Solution by Sreeraj P, M.Sc Physics