Q 12-03-138JEE MainJEE Main 2023 (11 Apr, Shift 1)Medium
In the circuit diagram shown in figure given below, the current flowing through resistance $3\ \Omega$ is $\dfrac x3$ A. The value of $x$ is ______.
Numerical value type. Enter your answer.
Answer: 1
The cells oppose each other, so the net emf is $8-4=4\ \text{V}$.
Total resistance: $0.5+1+4.5+\dfrac{3\times6}{9}=8\ \Omega$, so $I=0.5\ \text{A}$.
Current in $3\ \Omega$: $0.5\times\dfrac{6}{9}=\dfrac13\ \text{A}$, so $x=1$.
Solution by Sreeraj P, M.Sc Physics