Q 12-03-112JEE MainJEE Main 2023 (29 Jan, Shift 1)Easy
Ratio of thermal energy released in two resistors $R$ and $3R$ connected in parallel in an electric circuit is
Answer: (A) $3:1$
In parallel the voltage is common, so $H=\dfrac{V^2t}{R}\propto\dfrac1R$.
$$H_R:H_{3R}=\frac1R:\frac1{3R}=3:1$$
Solution by Sreeraj P, M.Sc Physics