An alternating voltage source V=260(628t) is connected across a pure inductor of 5 mH. Inductive reactance in the circuit is

(A) 3.14 Ω. X_L=ω L=628×5×10^-3=3.14 Ω.

Alternating Current question for JEE Main (JEE Main 2023 (31 Jan, Shift 2)), with solution

Q 12-07-075JEE MainJEE Main 2023 (31 Jan, Shift 2)Easy

An alternating voltage source $V=260\sin(628t)$ is connected across a pure inductor of $5\ \text{mH}$. Inductive reactance in the circuit is