A nucleus has mass number $\alpha$ and radius $R_\alpha$. Another nucleus has mass number $\beta$ and radius $R_\beta$.
If $\beta = 8\alpha$ then $R_\alpha/R_\beta$ is :
- A1
- B2
- C8
- D0.5
Answer and solution
Answer: Option D: 0.5
Concept. $R=R_0A^{1/3}$.
Step 1. Ratio. $\dfrac{R_\alpha}{R_\beta}=\left(\dfrac{\alpha}{8\alpha}\right)^{1/3}=\dfrac12$.
Answer. $0.5$ (Option D).
Point to note. $R\propto A^{1/3}$.