Number of photons of equal energy emitted per second by a 6 mW laser source operating at 663 nm is ______.
(Given : $h = 6.63\times10^{-34}$ J.s and $c = 3\times10^8$ m/s)
- A$10\times10^{15}$
- B$5\times10^{16}$
- C$5\times10^{15}$
- D$2\times10^{16}$
Answer and solution
Answer: Option D: $2\times10^{16}$
Concept. Photons per second $=\dfrac{\text{power}}{\text{energy per photon}}=\dfrac{P\lambda}{hc}$.
Step 1. Value. $\dfrac{6\times10^{-3}\times663\times10^{-9}}{6.63\times10^{-34}\times3\times10^8}=\dfrac{3.98\times10^{-9}}{1.99\times10^{-25}}=2\times10^{16}$.
Answer. Option D.
Point to note. $n=P\lambda/hc$.