Q 11-05-017NEETJEE MainEAMCET 2013 (Engineering)Easy
A ball at rest is dropped from a height of $12$ m. If it loses $25\%$ of its kinetic energy on striking the ground and bounces back to a height $h$, the value of $h$ is
Answer: (C) $9$ m
Concept. The kept $75\%$ of KE becomes PE at the top of the bounce.
Step 1. Height. $h = 0.75 \times 12 = 9$ m.
Answer. $9$ m (Option C).
Solution by Sreeraj P, M.Sc Physics