Q 11-05-011NEETJEE MainEAMCET 2008 (Engineering)Medium
A ball is dropped from a height $h$ on to a floor of coefficient of restitution $e$. The total distance covered by the ball just before the second hit is
Answer: (B) $h(1 + 2e^2)$
Concept. Rebound speed $ev$, so rebound height $e^2h$.
Step 1. Distance. Down $h$, up $e^2h$, down $e^2h$: $h(1 + 2e^2)$.
Answer. $h(1 + 2e^2)$ (Option B).
Solution by Sreeraj P, M.Sc Physics