Q 11-01-035NEETJEE MainTop questionEasy
The main scale of a vernier callipers is graduated in half-millimetres ($1\ \text{MSD} = 0.5\ \text{mm}$). 25 divisions of the vernier scale coincide with 24 divisions of the main scale. The least count of the instrument is
Answer: (C) $0.02\ \text{mm}$
$25\ \text{VSD} = 24\ \text{MSD} \Rightarrow 1\ \text{VSD} = \dfrac{24}{25}\ \text{MSD}$
$$\text{LC} = 1\ \text{MSD} - 1\ \text{VSD} = \frac{1}{25}\ \text{MSD} = \frac{0.5}{25}\ \text{mm} = 0.02\ \text{mm}$$
Solution by Sreeraj P, M.Sc Physics