Q 11-01-015NEETNEET 2020Top questionEasy
A screw gauge has least count of $0.01$ mm and there are $50$ divisions in its circular scale. The pitch of the screw gauge is :
Answer: (C) $0.5$ mm
$\text{LC} = \dfrac{\text{pitch}}{\text{number of circular divisions}}$, so
$$\text{pitch} = 0.01 \times 50 = 0.5\ \text{mm}$$
Solution by Sreeraj P, M.Sc Physics