Q 11-01-001NEETJEE MainTop questionEasy
The dimensional formula of Planck's constant $h$ is
Answer: (B) $[ML^2T^{-1}]$
Use $E = h\nu$, so $h = E/\nu$.
$$[h] = \frac{[ML^2T^{-2}]}{[T^{-1}]} = [ML^2T^{-1}]$$
This is also the dimension of angular momentum.
Solution by Sreeraj P, M.Sc Physics