Q 11-12-017NEETJEE MainEasy
The total translational kinetic energy of $2$ moles of a monatomic ideal gas at $300$ K is about ($R = 8.31$ J mol$^{-1}$ K$^{-1}$)
Answer: (C) $7.5$ kJ
$E = \dfrac{3}{2}nRT = \dfrac{3}{2} \times 2 \times 8.31 \times 300 \approx 7479$ J $\approx 7.5$ kJ.
Solution by Sreeraj P, M.Sc Physics