Q 11-12-010NEETNEET 2020Top questionEasy
The average thermal energy for a mono-atomic gas is : ($k_B$ is Boltzmann constant and T, absolute temperature)
Answer: (B) $\dfrac{3}{2}k_BT$
Concept. Equipartition: $\dfrac12k_BT$ per degree of freedom.
Step 1. Monatomic. 3 translational degrees of freedom: $E = \dfrac32k_BT$.
Answer. $\dfrac32k_BT$ (Option B).
Solution by Sreeraj P, M.Sc Physics