Q 11-12-010NEETNEET 2020Top questionEasy
The average thermal energy for a mono-atomic gas is : ($k_B$ is Boltzmann constant and T, absolute temperature)
Answer: (B) $\dfrac{3}{2}k_BT$
A monatomic molecule has 3 translational degrees of freedom, each with average energy $\dfrac{1}{2}k_BT$:
$$E = \frac{3}{2}k_BT$$
Solution by Sreeraj P, M.Sc Physics