In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions:
Answer: (C) $AB$ and $DC$
Concept. Lenz's law: the induced current opposes the relative motion; then the winding sets the current direction for each pole.
Step 1. Solenoid-1. The N pole moves away, so solenoid-1 attracts it: its face towards the magnet becomes S. For this winding, the right face is S when current flows $A \to B$.
Step 2. Solenoid-2. The S pole approaches, so solenoid-2 repels it: its face towards the magnet (left face) becomes S, i.e. its right face is N. That needs current $D \to C$.
Answer. $AB$ and $DC$ (Option C).
Solution by Sreeraj P, M.Sc Physics