Q 11-05-004NEETNEET 2025Top questionEasy
The kinetic energies of two similar cars A and B are $100$ J and $225$ J respectively. On applying breaks, car A stops after $1000$ m and car B stops after $1500$ m. If $F_A$ and $F_B$ are the forces applied by the breaks on cars A and B, respectively, then the ratio $F_A/F_B$ is
Answer: (B) $\dfrac{2}{3}$
Concept. Work–energy: $Fd = K$.
Step 1. Forces. $F_A = \dfrac{100}{1000} = 0.1$ N, $F_B = \dfrac{225}{1500} = 0.15$ N.
Step 2. Ratio. $\dfrac23$.
Answer. $\dfrac23$ (Option B).
Solution by Sreeraj P, M.Sc Physics