Q 11-07-039JEE MainEasy
The weight of a body on the Earth's surface is $90$ N. Find its weight, in newtons, at a height equal to twice the Earth's radius above the surface.
Numerical value type. Enter your answer.
Answer: 10
Concept. $W = W_0\left(\dfrac{R}{R + h}\right)^2$.
Step 1. Substitute. $\dfrac{90}{9} = 10$ N.
Answer. $10$.
Solution by Sreeraj P, M.Sc Physics