Q 12-11-001NEETEasy
The energy of a photon of wavelength $400\ \text{nm}$ is approximately (take $hc = 1240\ \text{eV nm}$)
Answer: (B) $3.1\ \text{eV}$
Concept. Photon energy $E = \dfrac{hc}{\lambda}$.
Step 1. Substitute. $\dfrac{1240}{400} = 3.1$ eV.
Answer. $3.1$ eV (Option B).
Solution by Sreeraj P, M.Sc Physics