Match List-I with List-II.
$$\begin{array}{|l|l|l|l|}\hline & \text{List I} & & \text{List II} \\ \hline \text{(a)} & \omega L > \frac{1}{\omega C} & \text{(i)} & \text{Current is in phase with emf} \\ \hline \text{(b)} & \omega L = \frac{1}{\omega C} & \text{(ii)} & \text{Current lags behind the applied emf} \\ \hline \text{(c)} & \omega L < \frac{1}{\omega C} & \text{(iii)} & \text{Maximum current occurs} \\ \hline \text{(d)} & \text{Resonant frequency} & \text{(iv)} & \text{Current leads the emf} \\ \hline \end{array}$$
Choose the correct answer from the options given below.
Answer: (A) (a)-(ii); (b)-(i); (c)-(iv); (d)-(iii)
(a) Inductive reactance dominates: current lags (ii). (b) Reactances cancel: current in phase (i). (c) Capacitive reactance dominates: current leads (iv). (d) At resonance the impedance is minimum, so the current is maximum (iii).
Solution by Sreeraj P, M.Sc Physics